Question

Q.9 please its given in the attachment

Answer 1

Answer:

Step-by-step explanation:

2^x = 3^y = 12

xlog2 = log12

x = log12/log2

ylog3 = log12

y = log12/log3

putting values of x and y in the equation, we get

((log12/log2) + 2(log12/log3))/(log12/log2)(log12/log3)

= ((log3×log12 + 2×log2×log12)/log2×log3)/(log12×log12/log2×log3)

= (log3.log12 + 2log2.log12)/log12.log12

= (log3 + 2log2)/log12

= (log3 + log2²)/log12

= (log3 + log4)/log12

= log(3×4)/log12

= log12/log12

= 1