Q.9 The angle of elevation of a ladder leaning against wall is 60" and the foot of the ladder is 12 m away
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1
Answer:
Let AB be the wall and BC be the ladder.
Then, ∠ACB=60∘ and AC=12m
AC /BC= cos60∘ = 1 /2
⇒BC=2×AC
=(2×12)m
=24 m
Answered by
1
Step-by-step explanation:
tan60=x/12
root3=x/12
root3×12=x
taking in the value of root 3 we get
1.732×12=x
20.784cm=x
thus our x that is the height of the ladder is 20.784 cm or 20.78 cm approx.
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