Question

Q.9 the average power required to lift a 100 kg mass through a height of 50 metres in approximately 50 seconds would be

Answer 1

Answer:

it's very simple

Explanation:

average power equals 1/2(mgh)

m=100kg

h=50m g=9.8 or 10

t=50s

so according to formula

case I

so according to formula

A. P=100*9.8*50/2

=980*50/2

=460*50/2

=23000 aur we can write it as 23kw

since a. p unit is kw or w

case 2

A. P=100*10*50/2

=250*100

=25000 or 25kw