Question

Q.9. The price of 3 chairs and 2 tables is 3500 rupees and price of 5 chairs and 3 tables is 5500 rupees, then find the price of 4 chairs and 4 table. *

a)6000

b)7500

c)8000

d)None of these



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Answer 1

Answer:

D) None of these its 1000

Step-by-step explanation:

Let x be table and y be chair

Equation:

2x+3y=3500……………(i)

3x+2y=4000……………(ii)

Solving eqn (i)

2x+3y=3500

Can as well be written as

2x=3500–3y

> x=[3500–3y]÷2…………(iii)

Using equation (iii) to solve equation (iii)

# 3x+2y=4000

Since we now know x,

# 3([3500–3y]÷2)+2y=4000

By solving the equation, will have,

10500–9y+4y=8000

Or,

9y-4y=10500–8000

>5y=2500

# y=500

Hence,taking any of the 3 equations can give us the value of x

3x+2y=4000

3x+(2×500)=4000

3x+1000=4000

3x=4000–1000

3x=3000

# x=1000

Thus,a table cost Rs.1000

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Answer 2

Answer:

a) 6000

Step-by-step explanation:

price of 2 tables and 3 chairs = 3500

price of 5 chairs and 3 tables = 5500

price of 1 chair  = 500

price of 1 table = 1000

price of 4 chairs = 500 x 4 = 2000

price of 4 tables = 1000 x 4 = 4000

price of 4 chairs and 4 tables = 2000 + 4000 = 6000