Question

Q. 9. The resistance of a wire of length 100 cm and of uniform area of cross-section 0.020 cm', is found to be 2.0 ohm calculate specific resistance of wire​

Answer 1

Explanation:

l=100cm=1m

area=0.02=0.000002m^2

specific resistance=(R×area)/length

2×0.000002×1

=4×10^-6ohm-m

Answer 2

Given that,

Length of wire, l = 100 cm = 1 m

Area of cross section of the wire, $A=0.02\ cm^2=0.02\times 10^{-4}\ m^2$

Resistance of the wire, R = 2 ohms

To find,

The specific resistance of wire.

Solution,

The Resistance of a wire is given by :

$R=\rho\dfrac{l}{A}$

$\rho$ is specific resistance of wire

$\rho=\dfrac{RA}{l}\\\\\rho=\dfrac{2\times 0.02\times 10^{-4}}{1}\\\\\rho=4\times 10^{-6}\ \Omega-m$

So, the specific resistance of the wire is $4\times 10^{-6}\ \Omega-m$.

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