Question

Q. 9) The sum of three consecutive prime numbers succeeding 55 is added to the sum
of three consecutive primes preceding 55. The number 55 is subtracted from the
resulting sum. What is the remainder ?
1) 275
2) 375
3) 175
4) 75​

Answer 1

Answer:

prime no. preceding 55 are 43 +47 +53=143

prime no. succeeding 55 are 59 +61+67=187

therefore,143+187=330

330-55=275

so answer is 275