Question

Q. 9. Which of the following is the value of the discriminant for √2x²-5x+√2=0​

Answer 1

Answer:

The given equation is √2x²—5x+√2 = 0. This equation is of the form of ax²+bx+c = 0. Hence, the discriminant of the equation is 17.

Answer 2

Answer:

2

Step-by-step explanation:

Equation: √2x²-5x+√2=0

√2x²-5x+√2=0Here, a = √2, b = -5, c = √2

√2x²-5x+√2=0Here, a = √2, b = -5, c = √2Thus,

Discriminant (D) = b^2 - 4ac

b^2 - 4ac= (-5)^2 - 4(√2)(√2)

b^2 - 4ac= (-5)^2 - 4(√2)(√2)= 10 - 4(2)

b^2 - 4ac= (-5)^2 - 4(√2)(√2)= 10 - 4(2)= 10 - 8

b^2 - 4ac= (-5)^2 - 4(√2)(√2)= 10 - 4(2)= 10 - 8= 2