Question

Q.9)Write chemical equation for the following: a) Finkelstein reaction b) Wurtz-Fittig reaction. c) Swartz reaction​

Answer 1

Answer:

by the body and We'll find Time Taken (t) using Second Equation of motion and that is : \begin{gathered}\:\underline {\pmb{\sf s \:=\: ut \:+\:\dfrac{1}{2} + at^2\:}}\\\end{gathered}

s=ut+

2

1

+at

2

s=ut+

2

1

+at

2

\begin{gathered} \twoheadrightarrow \sf s \:=\: ut \:+\:\dfrac{1}{2} + at^2\:\\\\\\\twoheadrightarrow \sf s \:=\: (\: 0\times t\:)\:+\:\dfrac{1}{2} + at^2\:\:\qquad \Bigg\lgroup \:Initial _{\:(Velocity)}\:=\:0\:m/s\:\Bigg\rgroup\:\\\\\\\twoheadrightarrow \sf s \:=\:\:\dfrac{1}{2} + at^2\:\\\\\\\twoheadrightarrow \sf s \:=\:\dfrac{1}{2} + 10 \:\times t^2\:\:\qquad \Bigg\lgroup \:Acc^n\:_{\:(Gravity)}\:=\:10\:m/s^2\:\Bigg\rgroup\\\\\\ \twoheadrightarrow \sf 59.4 \:=\: \dfrac{1}{2} + 10t^2\:\\\\\\\twoheadrightarrow \sf 59.4 \:=\: 5 t^2\\\\\\\twoheadrightarrow \sf 5t^2\:=\:59.4 \\\\\\ \twoheadrightarrow \sf t^2 \:=\: \dfrac{59.4}{5} \\\\\\ \twoheadrightarrow \sf t^2 \:=\: 11.88 \\\\\\\twoheadrightarrow \sf t \:=\: \sqrt{\Big( 11.88\Big)} \\\\\\\twoheadrightarrow \pmb {\underline {\boxed {\purple {\:\frak{ \:t\:\:=\:3.44\:sec\:}}}}}\:\bigstar \: \\\\\\\end{gathered}

Answer 2

a)R--CI or R--Br+Nal Acetone or Methanol

________________

R--I+NaCI or NaBr

. ( Finkelstein reaction)

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