Question

Q 94 Calculate the approximate molecular weight of a gas if, 2.29L of gas weighs 3.71g at 18°C and 765 torr.​

Answer 1

Answer:

32g/Mol yduduudduduyxyyd

Answer 2

Answer:

The approximate molar mass of the gas is 38.64 g/mol.

Explanation:

Given,

Volume of gas, V = 2.29 L

Weight of gas, W = 3.71g

Temperature,T = 18° C = 273.15 + 18 K = 291.15 K

Pressure,P = 765 torr

Gas constant, R = 0.082 L.atm/mol.k

Convert torr into atm:

1 atm = 760 torr

$1 torr = \frac{1}{760} atm$

$765 torr =\frac{765}{760} atm$

765 torr = 1.006 atm

So, according to ideal gas law equation

$PV=nRT$

By using this equation we can determine the number of moles of gas,n.

$n= \frac{PV}{RT}$

After putting all the values, we get:

$n = \frac{1.006*2.29}{0.082*291.15}$

$n= \frac{2.303}{23.87}$

n = 0.096 moles

Now ,

$Molar mass = \frac{W}{n}$

$Molar mass = \frac{3.71}{0.096}$

Molar mass = 38.64 g/mol

RESULT : The approximate molar mass of the gas is 38.64 g/mol.