Q. a 10 nano farad (10 x 10-9 F) parallel plate capacitor holds a charge of magnitude 50 micro C on each plate. if the plates are separated by a distance of 0.885 mm, what is the area of the plate ?
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C = ε₀A / d
From above equation
A = Cd / ε₀
= (10 × 10^-9 Farad × 0.885 × 10^-3 m) / (8.854 × 10^-12 Farad / m)
= 0.995 m²
≈ 1.0 m²
Area of plate is approximately 1.0 m²
From above equation
A = Cd / ε₀
= (10 × 10^-9 Farad × 0.885 × 10^-3 m) / (8.854 × 10^-12 Farad / m)
= 0.995 m²
≈ 1.0 m²
Area of plate is approximately 1.0 m²
saadyasinkhan:
Thank you so much
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