Question

Q. A 12 cm rod is held between a flashlight
and a wall as shown. Find the length of the
shadow on the wall if the rod is 45 cm from
the wall and 15 cm from the light.​

Answer 1

Answer:

48 cm

Step-by-step explanation:

Δ ADE ~ Δ ABC

AM ⊥ DE and AF ⊥ BC

$\frac{AM}{DE}$ = $\frac{AF}{BC}$

AM = 15 cm; DE = 12 cm; AF = 15 + 45 = 60 cm;

BC = $\frac{DE * AF }{AM}$ = $\frac{12*60}{15}$ = 48 cm