Question

Q. a,b,c are three positive integers less than 10 Where, (a+b+c)⁵=(100a+10b+c)² Find the value of a×b+c ?​

Answer 1

Step-by-step explanation:

(1) a = 1.5b and b = 1.5c --> a/b=3/2=9/6 and b/c=3/2=6/4 --> a/b/c=9/6/4 and as a, b, and c are the positive single digits, then a=9, b=6 and c=4 --> abc=964. Sufficient.

(2) a = 1.5x + b and b = x + c, where x represents a positive single digit --> multiple values are possible, for example: if x=2 then a=3+b and b=2+c --> abc can 631 (for c=1) be or 742 (for c=2). Not sufficient.

Answer: A.