Math, asked by Zara2340, 20 hours ago

Q. A ball is thrown at upward direction with 72km per hour find the time taken to reach at maximum height​​

Answers

Answered by llPRINCESSSOFIAll
6

Answer:

hii

Step-by-step explanation:

At maximum height the final velocity is zero. Thus, time taken to return initial position is 4 s and the maximum height is 20 m.

hope it will help you

Answered by bathwar23
4

Answer:

At maximum height the final velocity is zero. Thus, time taken to return initial position is 4 s and the maximum height is 20 m.

Step-by-step explanation:

Given Initial velocity of ball, u=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s

2

holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

v

2

−u

2

=2aH

0−(49)

2

=2×(−9.8)×H

⟹H=122.5 m

v=u+at

0=49−9.8t

⟹t=5 s

∴ Total time taken by ball to return to the surface, T=2t=10 s

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