Question

Q. A ball of mass 1 kg strikes a wall normally with the speed of 10 m/s and rebound with the speed of 5 m/s in opposite direction. The magnitude of change in momentum of the ball is - (a) 15 kg m/s (b) 10 kg m/s (c) 5 kg m/s (d) Zero

Answer 1

Explanation:

Impulse=change in momentum

Delta P=Pf-Pi

=m(vf-vi)

=1(5-(-10)

=1(15)

=15kg m/s

Answer 2

Answer:

∆P = 15 kg m/sec

Explanation:

Change in momentum =∆P

∆P = P(final) - P(initial)

∆P = m[v(final) - v(initial)]

∆P = 1 ( 5 -(-10) )

∆P = 15 kg m/sec

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