Question

Q.A block of 8 kg is moving with 4 m/s on a frictionless surface. This block compresses a spring and comes to rest. If spring constant is 2x10^4 N/m then find the compression in the spring.​

Answer 1

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A block of 9 kg moving with velocity of 4 m/s on frictionless surface the block comes into rest by compressing the springs if springs constant is 4×10^4 N/kg then find compression in the springs.

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Given A block of 9 kg moving with velocity of 4 m/s on friction less surface the block comes into rest by compressing the springs if springs constant is 4×10^4 N/m then find compression in the springs.

Energy possessed by a body by virtue of its position is potential energy and energy possessed by a body by virtue of its motion is kinetic energy.

From law of conservation of energy P.E = K.E

                                                  1/2 p x^2 = 1/2 m v^2

                                               x^2 = mv^2 / p

                                              x^2 = 9 x 4 / 40000

                                           x = √9 x 4 / 40000

                                         x = 3 x 2 / 200

                                         x = 3/100 m

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Answer 2

Explanation:

A block of 9 kg moving with velocity of 4 m/s on frictionless surface the block comes into rest by compressing the springs if springs constant is 4×10^4 N/kg then find compression in the spring

Given A block of 9 kg moving with velocity of 4 m/s on friction less surface the block comes into rest by compressing the springs if springs constant is 4×10^4 N/m then find compression in the spring

From law of conservation of energy P.E = K.E

1/2 p x^2 = 1/2 m v^2

x^2 = mv^2 / p

x^2 = 9 x 4 / 40000

x = √9 x 4 / 40000

x = 3 x 2 / 200

x=3/100