Q) A body is thrown vertically upward with velocity (u), the greatest height to which it will rise is,
a) ![u/g u/g](https://tex.z-dn.net/?f=u%2Fg)
b) ![u^{2}/2g u^{2}/2g](https://tex.z-dn.net/?f=u%5E%7B2%7D%2F2g)
c) ![u^{2}/g u^{2}/g](https://tex.z-dn.net/?f=u%5E%7B2%7D%2Fg)
d)
Answers
Answered by
1
Answer:
option b ) u^2 / 2g
hope it helps
Answered by
2
Explanation:
The body that is thrown vertically upward with velocity u will have final velocity v=0 at the greatest height h.
The body that is thrown vertically upward with velocity u will have final velocity v=0 at the greatest height h.Substituting the given values in the third equation of motion, v^2= u^2+2as
The body that is thrown vertically upward with velocity u will have final velocity v=0 at the greatest height h.Substituting the given values in the third equation of motion, v^2= u^2+2aswe have 0 =u^2 −2gh. (taking g in the upward direction)
The body that is thrown vertically upward with velocity u will have final velocity v=0 at the greatest height h.Substituting the given values in the third equation of motion, v^2= u^2+2aswe have 0 =u^2 −2gh. (taking g in the upward direction) or h=u^2/2g
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