Question

Q. A body of mass 5 kg moving with Velocity if 10m/s A force is applied to it so that in 25 seconds it attains the velocity of 35 m/s . Calculate the force .

Answer 1

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Given :-
Mass = 5 kg

U = 10 m/s

V = 35 m/s

T = 25 s

A = ?

F = ?


Let's use the First Equation of Motion

V = U + AT

35 = 10 + a × 25

35 - 10 = 25a

a = $\frac{25}{25}$

a = 1 m/s

Let's use the equation F=Mass× Acceleration

F = MA

F = 5 × 1

F = 5 N $\boxed{Ans}$



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Answer 2

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Given :

Initial velocity (u) = 10 m/s.

Final velocity (v) = 35 m/s.

Time Taken (t) = 25 secs.

To Find :

Acceleration (a) =?

Force (F) =?

Solution:

We will use first equation of motion here ;

★ v = u + at

⇒ 35 = 10 + a × 25

⇒ 35 - 10 = 25a

⇒ 25 a = 25

⇒ a = 25 / 25

⇒ a = 1 m/s²

Now,

We know that,

Force is the product of mass and acceleration.

∴ Force = mass × acceleration

⇒ Force = 5 × 1

⇒ Force = 5 N.

Hence,

The force acquired by the body is 5 N.

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