Physics, asked by hindvibiradar12, 6 months ago

Q.A body starts from rest. Find the distance
travelled by body till attains the velocity of
5 m/s. Its acceleration is 2 m/s2.
a) 3 m
b) 6 m
c) 9 m
d) None​

Answers

Answered by choudharymayank213
2

6.25 m

explanation in picture

Attachments:
Answered by GulabLachman
2

The distance travelled by the body is 6.25m

Given:

Velocity of the body = 5m/s

Acceleration of the body = 2m/s²

To Find:

Distance travelled by the body

Solution:

As per the given data -

Initial velocity = u = 0 m/s

Velocity of the body = v = 5m/s

Acceleration of the body = a = 2m/s²

Displacement = s = Not present

Now,

Applying the third equation of motion -

v² - u² = 2as

or

v² = u² + 2as

Substituting the values -

(5)² = (0)² + 2 (2)s

25 = 0 + 4s

s = 25/4

s = 6.25

Answer: The distance travelled by the body is 6.25m

#SPJ2

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