Q. A box weighing 15 N slides
down from the top of an inclined plane making
an angle of 30° with the horizontal. Calculate the
work done by the force of gravity in moving the
box 5.0 m along the plane. Take g = 10 m/s2 and
also assume that the force of friction is negligible.
Please help me,it's urgent
Answers
Answer:
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Class 11
>>Physics
>>Laws of Motion
>>Application of Newton's Laws of Motion
>>An inclined plane makes an angle 30^0 wi
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An inclined plane makes an angle 30
0
with the horizontal. A groove OA =5m cut in the plane makes an angle 30
0
with OX. A short smooth cylinder is free to slide down the influence of gravity. Find the time taken by the cylinder to reach from A to O. ( g=10m/s
2
)
135600
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Hard
Solution
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Verified by Toppr
Correct option is C)
As is clear from the diagram:
Component of gravity along the incline =gsin30
o
=10×0.5=5m/s
2
Component of gravity along lone OA =
o
)
o
=10×0.5×0.5=2.5m/s
2
Thus acceleration of the cylinder is 2.5m/s
2
along line OA.
Using s=ut+
2
1
at
2
⇒5=
2
1
×2.5×t
2
Solving t=2sec
Thus (c) is the correct option.