Question

Q) A bullet fired in a tree losses its 1/4 of kinetic energy in traveling a distance of 5 cm, before stopping it travels a further distance of ______ ?​

Answer 1

Answer:

Explanation:

2as=v2−u2

2×a×5=v2−u2

⇒2×a×5=43​u2−u2

⇒a=40−u2​

After 5 cm it loses 41​th of its initial KE.

The acceleration will be same throughout.

Again using 2as=v2−u2 when v becomes 0.

2×40−1​u2×s=−u2

⇒s=20

So bullet further travels 15 m.

Answer 2

Answer:

15 cm

Explanation: