Question

Q)A bullet of A bullet of mass 40 kg in horizontally fired with a velocity 300 m/s from a pistol of mass 4kg.what is the recoil velocity of the pistol?​

Answer 1

v'=recoil velocity of gun=mv/(M+m), where M=mass of gun and m=mass of bullet.

Therefore, v'=40×10^(-3)×300/(0.05+40)

=12/40.05=0.3m/s