Q. a bullet of mass 0.03 kg and moving with a velocity of xm/s hit a target with a force of 187.5 N. If the bullet penetrate 0.8m in the target then find the value of x?
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Explanation:
m = 0.03 kg
F = 187.5 N
s = 0.80 m
v = x
x = ?
KE of the bullet = ½ mx^2
= ½ ×0.03×x^2
Work done by the bullet on the wood = Fs
= 187.5×0.80
By conservation of energy
KE = Work done
=> ½ ×0.03×x^2 = 187.5×0.80
=> x = √{(187.5×0.80×2)/0.03}
=> x = 100 ms^-1
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