Question

Q. A bullet of mass 150 g is fired with a velocity of 200 m/s from a pistol of 2 Kg find the recoil velocity of the pistol.?

Answer 1

let the velocity of bullet be V1 = 200m/s
the mass of bullet be M1 = 0.15kg
the mass of gun be M2 = 2kg
the velocity of gun be V2 = V

By applying law of conservation of momentun

M1V1 = M2V2
0.15×200 = 2×V
30÷2 = V
-15 = V

therefore the recoil velocity of the pistol is -15m/s because it will move in backward direction after firing the bullet

hope ut helps

Answer 2

MU = mv

0.15*200 = 2*v

v = 15 m/s