Question

Q. A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.
_____________________
give answers clearly otherwise your 20 answers will be deleted
________________​

Answer 1

Answer:

Question 16: A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a)the speed acquired, (b) the distance travelled. Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration. Thus, bus will travel a distance of 720 m in the given time of 2 minute

Answer 2

Question:-

A bus starting from rest moves with a uniform acceleration of 0.1 ms^(-2) for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Required Answer:-

Given:-

• The initial velocity of the bus u = 0 m/s
• Acceleration of the bus a = 0.1 ms^(-2)
• Time t = 2 minutes = 120 seconds

To Find:-

• The speed acquired.
• The distance travelled.

Solution:-

(a) The speed acquired:-

We know that:-

$\\\underline{\boxed{\rm{v = u + at}}}$

Substituting the values:-

$\\ \sf{\implies{\bold{v} = 0 + 0.1 {ms}^{ - 2} \times 120s}}$

$\\ \sf{\implies{\bold{v} = 0 + 12 {ms}^{ - 1}}}$

$\\ \sf{\therefore{\bold{v} = \red{12 {ms}^{ - 1}}}}$

Hence, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.

(b)The distance travelled:-

We know that:-

$\underline{\boxed{\rm{s = ut + \dfrac{1}{2} a {t}^{2}}}}$

Substituting the values:-

$\\\sf{\implies{\bold{s} = 0 \times 120s + \dfrac{1}{2} \times 0.1 {ms}^{ - 2} \times {120s}^{2}}}$

$\\ \sf{\implies{\bold{s} = 0 + \dfrac{1}{2} \times 0.1 {ms}^{ - 2} \times 14400 {s}^{2}}}$

$\\ \sf{\implies{\bold{s} = \dfrac{1}{2} \times 1440m}}$

$\\ \sf{\therefore{\bold{s} = \red{720m}}}$

Hence, the bus will travel 720m .