Question

Q. A car accelerates uniformly from 36 km/h to 76 km/h in 5 sec.calculate (a) the acceleration
and (b) the distance covered by car in chat time.​

Answer 1

Explanation:

Q1. Amount of region occupied by a solid is called its _______

a) Area

b) volume

c) TSA

d) perimeter

Q2. The correct formula representing area of four walls and top is:

a) 2l+2b

b) 2lb+2bh

c) 21h+2bh

d) 21h+2lb

Q3. Exponential form of 0.0000007 is:

.

.

.

.

Answer 2

Answer:

Acceleration=20/9=2.223 and distance=77.78 m

Explanation:

Using Newton's law of Motion

acceleration= Change in velocity/Change in time

a=v-u/t

=21.11-10/5

=2.223 m/s^2

S= ut+1/2at^2

=10*5+0.5*2.223.25

=77.778 m