Question

q. a car weight 1500kg and travelling at 40m/sec stop at a distance of 25m retairing uniformly what s the work done by the break

Answer 1

Answer:

v2=u2+2as

final velocity is zero cause car has to be stop

40×40 = 2a×25

a=32m/s2

work done = force ×distance

=1500×32×25

=12000kj