Q A cone of height 8m has curved surface area of 188.4m sq the radius will be
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Given, height of the cone h = 8. Let r is the radius and l is the slant height of the cone. Given curved surface area of the cone = 188.4 .
CSA of a cone = πSR = 188.4 m2. S = 188.4/( 3.14xR) = 60/R. R2 = (S2-h2). R2 = (60/R)2- 8 2. R4+ 64R2 - 3600 = 0. r2 + 64r - 3600 = 0 ...
H=8mCSA = 188.4⇒2πrh = 188.4⇒r = 188.4/2πh = 188.4/(2×3.14×8) = 3.75mvolume = πr²h = 3.14×3.75²×8 = 353.25 ...
CSA of a cone = πSR = 188.4 m2. S = 188.4/( 3.14xR) = 60/R. R2 = (S2-h2). R2 = (60/R)2- 8 2. R4+ 64R2 - 3600 = 0. r2 + 64r - 3600 = 0 ...
H=8mCSA = 188.4⇒2πrh = 188.4⇒r = 188.4/2πh = 188.4/(2×3.14×8) = 3.75mvolume = πr²h = 3.14×3.75²×8 = 353.25 ...
krish9548:
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