Q)
a)derive an expression to calculate the kinetic energy of a body.
b)an object of mass 70kg is raised at the height of 10m above the ground.what is its potential energy
c) of the object is allowed to fall find its kinetic energy when it is halfway down (take g=10m/s^2).
Explain why sum of kinetic and potential energy remain unchanged for a falling object at all points during its fall.
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Answer:
a) Kinetic energy = 1/2 mv^2
b) Potential energy = mgh = 70*10*10 = 7000N
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