Math, asked by student8961, 4 days ago

Q. A does 7/18th of a work in 14 days. Then he completes the remaining work with the help of B in 10 days. In how many days can B alone do the work.​

Answer is 30 days but how (solution) ?​

Answers

Answered by davendra2000
0

Answer:

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Step-by-step explanation:

B will require 10 days to complete the whole work alone.

A does 7/10th of the work in 14 days.

So he will require 20 days to complete the whole work.

After 14 days 3/10th of the work is remaining.

Of this when they work together A does 1/20x2 or 1/10 th of the work and the balance 2/10 of the work is done by B.

To do 1/5th of the work B requires 2 days.

To do the whole work he will require 10 days.

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