q) a farmer divides his herd of x cows among his 4 sons so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 7 cows. then x is equal to
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That’s the answer. Hope you understand the handwriting.
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Let total cows be x
No. of cows given to,
Son1= x/2
son2= x/4
son3= x/5
son4= 7
All these add up to total no. of cows in the herd.
i.e., x= (x/2) + (x/4) + (x/5) + 7 ------------(1)
x - (x/2) - (x/4) - (x/5) = 7
x[1-0.5-0.25-0.20] =7
x[0.05] = 7
5x = 700
x=140
You can verify the answer by substituting in eq(1)
No. of cows given to,
Son1= x/2
son2= x/4
son3= x/5
son4= 7
All these add up to total no. of cows in the herd.
i.e., x= (x/2) + (x/4) + (x/5) + 7 ------------(1)
x - (x/2) - (x/4) - (x/5) = 7
x[1-0.5-0.25-0.20] =7
x[0.05] = 7
5x = 700
x=140
You can verify the answer by substituting in eq(1)
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