Question

Q. A farmer moves along the boundary of a square field of side 40 m in 40 seconds what will be the magnitude of displacement of the farmer at the end of 2 minutes 40 seconds from the initial position
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Answer 1

Answer:

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters=Totaldistance/perimeter

=3.5

At this point, the farmer is at a point say B from the origin O

Thus the displacement s= √10^2 + √10^2

from Pythagoras theorem s=10√2

=14.14m

Explanation:

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