Question

Q) A farmer moves along the boundary of a square field of side 20 m in 80 s. What will be the magnitude of displacement of the farmer at the end of 1 minutes 10 seconds from his initial position?​

Answer 1

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Answer 2

Answer:

side of the square = 20m

perimeter / total distance = 4×20 = 80m

80sec = 80m

1 sec = 80/80= 1m

1min 10 sec = 60+10 = 70 sec

in 70 sec = 1×70 = 70m

displacement = 80m-70m= 10m

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