Question

Q] A flywheel is revolving with a constant angular velocity. A chip of its rim breaks and
flies away. What will be the effect on its angular velocity?

[2 mark Que's]​

Answer 1

Refer the attachment

hope it helps

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Answer 2

${ \underline{ \underline{ \tt{ \red{ \huge{QUESTION}}}}}}$

A flywheel is revolving with a constant angular velocity. A chip of its rim breaks and flies away. What will be the effect on its angular velocity ?

${ \underline{ \underline{ \tt{ \red{ \huge{ANSWER}}}}}}$

initially the flywheel was revolving with a constant angular velocity.

${ \boxed{ \boxed{ \sf{ \green{angular \: momentum= l \times w}}}}}$

${ \dashrightarrow{ \sf{ l = { \green{moment \: of \: inertia}}}}} \\ { \dashrightarrow{ \sf{w = { \green{angular \: velocity}}}}}$

${ \underline{ \purple{ \sf{l(moment \: of \: inertia) = m {r}^{2} }}}}$

when the chip of the rim breaks and fly away , it's mass will deacrease and thus , it's moment of inertia decreases .

to conserve the angular momentum , its angular velocity must increase as the chip of the rim breaks and fly away.