Question

Q. A game of chance consists of an arrow which comes to rest, pointing at 1 of the regions 1,2 or 3. O is the centre of the circle. OC Of perpendicular to AB. find the probability that
a. arrow is resting on 3
b. arrow is resting on 1
c. arrow is not resting on 2

Answer 1

Answer:

Step-by-step explanation:

A circle is there whose center is O.

So the circle is divided into 3 parts

Two quadrants and one semicircle...

Total = 360 [Circle forms 360 degree]

a) --------

P(3) = 180 / 360 [ 3rd part is a semicircle therefore it is 180 degree]

Therefore

P(3) = 1/2 .................

b) ---------------

P(1) = 90/360 [quadrant forming 90 degree ]

Therefore

P(1) = 1/4.................

c) ---------------

P(E) = 270/360 [ accept 2 means 360-90 = 270 ]

Therefore

P(E) = 3/4 .............

Hope you understood

Hope helpful mate ❤❤❤

Mark as brainlist answer

Tnx

Answer 2

Step-by-step explanation:

please refer the attachment

I hope this helps you