Question

Q. A gas mixture contains 160 g O2 and 320 g O3. The molar ratio of O3 to O2 in the mixture will be ??

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Answer 1

Answer:

$\huge{ \boxed{68gNH_3}}$

Answer 2

Step-by-step explanation:

Volume of Nitrogen =24 g Molar mass of N

2

=28 g

Volume of Oxygen =32 g Molar mass of O

2

=32 g

Volume of Hydrogen =44 g Molar mass of H

2

=2 g

Mole number=

Molar mass

Given mass

Mole number N

2

=24/28=0.9

Mole number O

2

=32/32=1

Mole number H

2

=44/2=22

Total moles =0.9+1+22=23.9=24

Mole fraction of H

2

=

Total moles

No. of moles of hydrogen

=22/24=0.91