Question

Q: A logic circuit with an output X = ABC + AC consists of
e TWO AND gates, One OR gate.
TWO AND gates TWO OR gates,
O
D
TWO AND gates, One OR gate. O
TWO AND gates, One OR gate, One NOT gate​

Answer 1

Answer:

There are 3 AND gate and 1 OR gate required to produce output X.

Explanation:

Given:

A, B, and C are three input lines. A, B, and C can have values either 0 or 1.

Given Output: X=ABC+AC

$X=A.B.C+A.C$

Here,  "  $.$  "  represents an AND gate,

and "  $+$  " represents an OR gate.

There are three "   $.$  " in the output expression. Thus, there must be three AND gate.

There is only one "  $+$  " in the output expression. Thus, there must be one OR gate.

Hence, there are 3 AND gate and 1 OR gate required to produce output X.

[NOTE: If the expression is reduced, then output essentially becomes

X = A.C, this expression would require only 1 AND gate. ]

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Answer 2

There are 3 AND gate and 1 OR gate required to produce output X.

What is the function of and/or gate?

• The function of an OR gate is to find the maximum between the inputs which are binary in nature.
• It is one of the basic gates used in Boolean algebra and electronic circuits like transistor-transistor logic, and complementary metal-oxide semiconductors make use of it.

How is an AND gate made?

• A simple 2-input logic AND gate can be constructed using RTL Resistor-transistor switches connected together as shown below with the inputs connected directly to the transistor bases.
• Both transistors must be saturated “ON” for an output at Q.

What is positive OR gate?

• Positive Logic OR gate.
• The Positive Logic OR gates output achieves its ACTIVE state, (HIGH), when “one or more of its inputs” achieve their ACTIVE state, (HIGH).
• Negative Logic OR gate.
• The Negative Logic OR gates output achieves its ACTIVE state, (LOW), when “all of its inputs” achieve their ACTIVE state, (LOW).

What is a negative AND gate?

• A Negative-AND gate functions the same as an AND gate with all its inputs inverted (connected through NOT gates).
• In keeping with standard gate symbol convention, these inverted inputs are signified by bubbles.

According to the question:

Given:

A, B, and C are three input lines. A, B, and C can have values either 0 or 1.

Given Output: X=ABC + AC.

X=$A \cdot B \cdot C+A \cdot C$.

Here,  " . "  represents an AND gate.

and " +  " represents an OR gate.

There are three "  .   " in the output expression.

Thus, there must be three AND gate.

There is only one " +  " in the output expression.

Thus, there must be one OR gate.

Hence, there are 3 AND gate and 1 OR gate required to produce output X.

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