Question

Q.A man faces north and covers 12 km., turns west and covers 6 km. Then turned south and covers 3 km, and turns west again and covers 6 km. How far is he from the starting point?

Answer 1

To find:

How far is the man from the starting point?

Step-by-step explanation:

( Refer to the given attachment. )

• The man started from the point A and reached the point B, then to point C, D and lastly to E.

• Here, AB = 12 km, BC = 6 km, CD = 3 km, DE = 6 km.

• We have to find: AE = ? km

• We join E, F and F, A.

• Here, CD + EF = AB
• ⇾ 3 + EF = 12
• ⇾ EF = 9
• ∴ EF = 9 km

• Again, AF = DE + BC
• ⇾ AF = 6 + 6
• ⇾ AF = 12
• ∴ AF = 12 km

• Now, since AFE is a right-angled triangle, we write;
• EF² + AF² = AE²
• ⇾ AE² = 9² + 12²
• ⇾ AE² = 81 + 144
• ⇾ AE² = 225
• ⇾ AE² = 15²
• ⇾ AE = 15
• ∴ AE = 15 km

Answer:

The man is 15 km far from the starting point.

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