Q) A man in a balloon rising vertically with an acceleration of 4.9 ms–2 releases a stone 2s after the balloon is let go from the ground. The greatest height above the ground reached by the stone?.
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Explanation:
a=4.9 m/s^2, t=2
v=u + at
=4.9 * 2
= 9.8 m/s
Height at this point
h=1/2 at^2
=0.5*4.9*4
=9.8 m
The stone will attain further height s
1/2mv^2= mgs ; s=h
s=v^2/2g
=4.9 m
Therefore the greatest height reached by stone above the ground
H=h+s
=9.8+4.9
=14.7 m
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