Math, asked by student8961, 3 days ago

Q) A metal box without lid has the external dimensions 1.04 mx 0.54 mx 0.32 m. If the thickness of the box is 2 cm, find (i) the internal dimensions of the box and (ii) the volume of the metal used to make this box.
(step wise explanation) ​

Answers

Answered by hariomyadavu
0

answer is = 0.179712 M^3

Step-by-step explanation:

given: dimensions 1.04m,0.54m,0.32m

To find: internal dimension and volume

solution:

1 . > so the internal dimensions of the box is-

1.04m=104 cm

0.54m=54 cm

0.32m=32  cm

now subtract 2 cm thickness from each side , so side become

102 cm , 52 cm , 30 cm,

now multiple it =>    102 * 52 * 30 = 1,59,120 cm^3

now change into M, so 159120/100 M^3

so the dimension is 1591.2 M^3

2.> so the volume of the metal is to make the box are-

formula = height * length * breath

            =  1.04 * 0.54 * 0.32

             =0.179712 M^3

so our volume of metal is 0.179712 M^3

Answered by harshlodam
0

Answer:

refer the images for the answer

:v

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