Question

Q] A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of
0.2 ms-2 . Calculate the speed of the motor cycle after 10 second, and the
distance travelled in this time.

Answer 1

We have been given that motorcycle moving with speed of 5 m/s accelerating at 0.2 m/s²

We have to find speed of motorcycle after 10 seconds & distance travelled in 10 seconds.

Solution

1) Initial speed of motorcycle = 5 m/s

Acceleration = 0.2 m/s²

Time taken = 10 seconds.

Using 1st equation of motion :

☛ v = u + at

➠ v = 5 + (0.2 × 10)

➠ v = 5 + 2

➠ v = 7 m/s

Hence, speed of motorcycle after 10 seconds = 7 m/s

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2) We can find distance travelled by motorcycle in 10 seconds in 2 methods.

We will use 1st method here :

Using 2nd equation of motion :

☛ s = ut + ½ at²

➲ s = (5 × 10) + ½(0.2 × 10²)

➲ s = 50 + ½(0.2 × 100)

➲ s = 50 + ½(20)

➲ s = 50 + 10

➲ s = 60 m

Hence, distance travelled by motorcycle in this time = 60 m.

Answer 2

Answer:

Explanation:

Given :-

Initial speed, u = 5 m/s

Acceleration, a = 0.2 m/s²  

Time, t = 10 s

To Find :-

Distance, S= ??

Final velocity, v = ??

Formula to be used :-

1st equation of motion i.e v  = u +  at

3rd equation of motion i.e  v²  = u² + 2aS

Solution :-

Putting all the values, we get

v  = u +  at

⇒ v = 5 + 0.2 × 10  

⇒ v = 5 + 2

⇒  v = 7 m/s

Now, we will find Distance, S

v²  = u² + 2aS

⇒  72 =  52  + 2 × 0.2 × S  

⇒  49 = 25 + 0.4S  

⇒  49 - 25 = 0.4S

⇒  0.4S = 24  

⇒ S = 24/0.4  

⇒ S = 60 m

Hence, speed and distance traveled by motorcycle is 7 m/s and 60 m.