Question

Q. A particle moving with uniform acceleration
has velocity of 6 ms at a distance 5 m from
the initial position. After moving another
7 m the velocity becomes 8 ms. The initial
velocity and acceleration of the particle are
a) 2 ms-: 4 ms?
by4 ms"; 2 ms
c) 4 ms'; 4 ms
d) 6 ms-1 ; 1 ms-2​

Answer 1

Explanation:

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$let \: uniform \: acceleration \: is \: a \: \\ \\ vb \: = 6m |s \\ \\ vc = 8m |s| \\ \\ v \ \frac{2}{b} - v \ \frac{2}{a} = 2a(5)......(1) \\ \\ v \ \frac{2}{a} - v \ \frac{2}{b} = 2a(7).....(2) \\ \\ from \: 2 \: \frac{64 - 36}{14} = a \\ \\ a = 2m |s| 2 \\ \\ from \: 1 \: v \times \frac{2}{b \: } - 2a(s) = {v}^{2} a \sqrt{36 - 20 = v |a| } \\ \\ = v |a \: | = 4m |s|$

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Answer 2

a) 2 ms-: 4 ms

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