Q A racing car has a uniform acceleration of 5 m/s. What distance will it cover in 20 so after starting from rest.
Answers
Answered by
18
Given that:
a=5m/s^2
u =0 (as it starts from rest)
t =20s
Using the second equation of motion
s=ut +1/2at^2
s= 0 (20) + 1/2 (5)(20)(20)
= 5 (10)(20)
= 1000m
a=5m/s^2
u =0 (as it starts from rest)
t =20s
Using the second equation of motion
s=ut +1/2at^2
s= 0 (20) + 1/2 (5)(20)(20)
= 5 (10)(20)
= 1000m
Answered by
20
Answer:
acceleration=5m/sec²
time=20sec
distance=(to be calculated)
initial velocity (u) =0(as car starts from rest)
Here we use the second equation of motion which is
s = ut + 1/2at²
s = 0×20 + 1/2×5×20²
s = 1/2×5×400
s = 5×200
Hence s = 1000m
HOPE IT HELPS!
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