Question

Q A racing car has a uniform acceleration of 5 m/s. What distance will it cover in 20 so after starting from rest.

Answer 1

Given that:
a=5m/s^2
u =0 (as it starts from rest)
t =20s
Using the second equation of motion
s=ut +1/2at^2
s= 0 (20) + 1/2 (5)(20)(20)
= 5 (10)(20)
= 1000m

Answer 2

Answer:

acceleration=5m/sec²

time=20sec

distance=(to be calculated)

initial velocity (u) =0(as car starts from rest)

Here we use the second equation of motion which is

s = ut + 1/2at²

s = 0×20 + 1/2×5×20²

s = 1/2×5×400

s = 5×200

Hence s = 1000m

HOPE IT HELPS!