Physics, asked by Anonymous, 1 month ago

Q] A railway track goes around a curve having a radius of curvature of 1 km. The
distance between the rails is 1 m. Find the elevation of the outer rail above the inner rail so that there is no side pressure against the rails when a train goes round the curve
at 36 km / hr.​

Answers

Answered by shadowsabers03
129

Given,

  • radius of curvature, \sf{r=1\ km=1000\ m}
  • distance between the rails, \sf{d=1\ m.}
  • speed of the train, \sf{v=36\ km\,h^{-1}=10\ m\,s^{-1}}

Let \sf{g=10\ m\,s^{-2}.}

There would be no side pressure against the rails when the train moves along the rail with maximum safe speed, which is given by,

\sf{\longrightarrow v^2=rg\tan\theta}

Then the angle of elevation will be,

\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{v^2}{rg}\right)}

\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{10^2}{1000\times10}\right)}

\sf{\longrightarrow \theta=\tan^{-1}\left(\dfrac{1}{100}\right)}

\sf{\longrightarrow \theta=0.01\ rad}

Then the elevation of outer rail will be given by,

\sf{\longrightarrow h=d\sin\theta}

\sf{\longrightarrow h=1\times\sin(0.01)}

\sf{\longrightarrow\underline{\underline{h=0.01\ m}}}


Anonymous: Awesome answer, Thank you !
Answered by Toxicbanda
37

Answer:

  • Elevation of outer rail above the inner rail = 0.01 m

Explanation:

Given:

  • Radius of curvature (r) = 1 km = 1000 m
  • Distance between the rails (d) = 1 m
  • Speed of train (v) = 36 km/h

To Find:

  • Elevation of outer rail above inner rail (h).

Now, firstly we will convert speed into m/sec,

\implies{\sf{\dfrac{36\times 5}{18}\;m/sec}}

\implies{\bf{10\;m/sec}}

Now, the angle of elevation would be,

\implies{\sf{\theta = \tan^{-1}\bigg(\dfrac{v^{2}}{rg}\bigg)}}

Let, g = 10 m/s

\implies{\sf{\theta = \tan^{-1}\bigg(\dfrac{10^{2}}{1000\times 10}\bigg)}}

\implies{\sf{\theta = \tan^{-1}\bigg(\dfrac{100}{10000}\bigg)}}

\implies{\sf{\theta = \tan^{-1}\bigg(\dfrac{1}{100}\bigg)}}

\implies{\boxed{\sf{\theta =0.01\;rad}}}

Now, the elevation of outer rail will be,

\implies{\sf{h=d\sin \theta}}

\implies{\sf{h=1\times \sin\times 0.01}}

\implies{\boxed{\sf{h=0.01\;m}}}

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