Question

Q. A right triangle ABC with sides 8 cm , 15 cm and 17cm is revolved about the side 15 cm.Find the volume of the solid so obtained.​

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Answer 1

Answer:

Step-by-step explanation:

Diameter = 8cm

Length = 17cm

Height = 15cm

We know that the volume of cube is

Where,

π = 22/7 or 3.14

r = radius

h = height

As it is given that we have to use radius that's why we have to calculate radius first.

We know that:-

where,

d = diameter

r = radius

=>(1/3) ×(22/7) ×4²×15

=>(1/3) ×(22/7) ×16×15

=>(22/7) ×16×5

=>251.428

Hence, the volume of the solid formed by right angle triangle is (251.42cm³).

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Answer 2

Answer:

×3.14×12×12×25=3768cm

×3.14×12×12×25=3768cm Surface area of the double cone

×3.14×12×12×25=3768cm Surface area of the double cone=π×AO×AB+π×AO×AC

×3.14×12×12×25=3768cm Surface area of the double cone=π×AO×AB+π×AO×AC=π×AO(AB+AC)

×3.14×12×12×25=3768cm Surface area of the double cone=π×AO×AB+π×AO×AC=π×AO(AB+AC)=3.14×12×(15+20)

×3.14×12×12×25=3768cm Surface area of the double cone=π×AO×AB+π×AO×AC=π×AO(AB+AC)=3.14×12×(15+20)=3.14×12×35=1318.8cm

hope it helps you

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