Q. A shopkeeper sold two laptops. The cost price of each laptop was ₹35,600. He sold one at a profit of ₹1,450 and other at a loss of ₹960. Find the selling price of both the laptops.
Answers
Answered by
1
Answer:
Let cost price of laptop be Rs. x
∴ Profit =
100
15x
Rs
∴ selling price =Rs(
100
15x
+x)=Rs.
100
115x
New selling price =Rs. (
100
115x
−
100
115x
×
100
10
)
=Rs.
100
115x
(
100
90
)
=Rs.
1000
1035x
∴ Profit =(
1000
1035x
−x)=Rs.
1000
35x
Now,
1000
35x
=1050
∴ x=30,000
∴ Cost price of Laptop =Rs. 30,000
Answered by
0
Step-by-step explanation:
Let cost price of laptop be Rs. x
∴ Profit =
100
15x
Rs
∴ selling price =Rs(
100
15x
+x)=Rs.
100
115x
New selling price =Rs. ( 100 -115x100×115x100-10)
=Rs.
100
115x
(
100
90
)
=Rs.
1000
1035x
∴ Profit =(
1000
1035x
−x)=Rs.
1000
35x
Now,
1000
35x
=1050
∴ x=30,000
∴ Cost price of Laptop =Rs. 30,000
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