Q. A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm, and the diameter of the base is 4 cm. Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference between the volumes of the cylinder and the toy. (Take π = 3.14)
⠀
- Don't spam :)
Answers
Answer:
hopefully answerd
Step-by-step explanation:
pls mark me as brainliests answer
Given :
- The hieght of cone = 2cm
- Diameter at base of cone = 4cm
- Hence, Diameter of Hemisphere = 4cm
To Find :
- The volume of toy
- The volume of cylinder which circumscribe the toy
Formula To Be Applied :
Here, We will use the formula of volume of Hemisphere, Cone and cylinder :
- Volume of Hemisphere = (⅔)πr²
- Volume of cone = πr²h/3
- Volume of cylinder = πr²h
Solution :
Given, Height of cone = 2cm
Base Diameter of cone = 4cm
or, Radius of cone = 2cm
Hence, volume of cone :
Hence, The volume cone = 8.373 cm³
__________________________
Given, Diameter of Circle = 4cm
or, Radius = 2cm
Hence, volume of Hemisphere
Hence, volume of Hemisphere = 16.746 cm³
__________________________
Hence, total volume of toy
= 16.746+8.373
= 25.12 cm³
Hence, Volume of toy = 25.12 cm³
__________________________
Now, we know that if two geometric figurs are circumscribed, they are touching there most of the point without crossing it.
Hence, Hieght of the cylinder = 2+2 cm = 4cm
Radius of cylinder = 2cm
Hence, Volume of cylinder:
Hence, Volume of Cylinder = 50.24 cm³
__________________________
Hence, Difference In volume
= Volume of Cylinder-Volume of Toy
= 50.24-25.12
= 25.12 cm³
Hence, Difference In volume = 25.12cm³