Math, asked by Anonymous, 9 hours ago

Q. A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm, and the diameter of the base is 4 cm. Determine the volume of the toy. If a right circular cylinder circumscribes the toy, find the difference between the volumes of the cylinder and the toy. (Take π = 3.14)

- Don't spam :) ​

Answers

Answered by gindu1704
0

Answer:

hopefully answerd

Step-by-step explanation:

pls mark me as brainliests answer

Attachments:
Answered by YourHelperAdi
8

Given :

  • The hieght of cone = 2cm
  • Diameter at base of cone = 4cm
  • Hence, Diameter of Hemisphere = 4cm

To Find :

  • The volume of toy
  • The volume of cylinder which circumscribe the toy

Formula To Be Applied :

Here, We will use the formula of volume of Hemisphere, Cone and cylinder :

  • Volume of Hemisphere = (⅔)πr²
  • Volume of cone = πr²h/3
  • Volume of cylinder = πr²h

Solution :

Given, Height of cone = 2cm

Base Diameter of cone = 4cm

or, Radius of cone = 2cm

Hence, volume of cone :

 \tt{ \implies volume =  \pi  {r}^{2}  \frac{h}{3} }

 \tt{ \implies v = 3.14 \times 2 \times 2 \times 2 \frac{2}{3} }

  \tt{ \implies v =  \frac{25.12}{3}}

 \tt{volume  \: of \: cone = 8.37 \bar{3}}

Hence, The volume cone = 8.373 cm³

__________________________

Given, Diameter of Circle = 4cm

or, Radius = 2cm

Hence, volume of Hemisphere

 \tt{volume \:  =  \frac{2}{3}  \pi  {r}^{3} }

 \tt{ \implies volume =  \frac{2}{3} \times 2 \times 2 \times 2 \times 3.14}

 \tt{ \implies volume =  \frac{16}{3} \times 3.14}

 \tt{ \implies volume = 16.74 \bar{6}}

Hence, volume of Hemisphere = 16.746 cm³

__________________________

Hence, total volume of toy

= 16.746+8.373

= 25.12 cm³

Hence, Volume of toy = 25.12 cm³

__________________________

Now, we know that if two geometric figurs are circumscribed, they are touching there most of the point without crossing it.

Hence, Hieght of the cylinder = 2+2 cm = 4cm

Radius of cylinder = 2cm

Hence, Volume of cylinder:

 \tt{ volume =  \pi  {r}^{2} h}

 \tt{ \implies v = 3.14 \times 2 \times 2 \times 4}

 \tt{ \implies volume \: of \: cylinder = 50.24 \:  {cm}^{3} }

Hence, Volume of Cylinder = 50.24 cm³

__________________________

Hence, Difference In volume

= Volume of Cylinder-Volume of Toy

= 50.24-25.12

= 25.12 cm³

Hence, Difference In volume = 25.12cm³

Hope it helps you !

Similar questions