Question

Q. A square wire of side 3 cm is placed 25 cm away from a concave mirror of focal length 10 cm. What is the area enclosed by the image of the wire? The centre of the wire is on the axis of the with it's two sides normal to the axis.
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Answer 1

Answer:

f1=u1+v1

 v1=−101−−251=−503

 v=−350

 m=hh′=−uv 

h is the height of the object

 3h′=−−25(3−50) h=−2cm

 =(−2cm)2=4cm2 so the area enclosed by image of wire.

Answer 2

Explanation:

1÷f = 1÷u + 1÷v

1÷v + 1÷-10 - 1÷-25 = - 3÷50

v = - 50÷3

m = h÷h = - v÷u

h is the height of the object

h÷3 = - (-50÷3)÷-25 h = -2 cm

(-2 cm)² 4cm² so the area enclosed by image of wire

I think this should be the answer.

I this will help you.