Question

Q. A stone is attached to a string 1m long and then whirled round in a horizontal cirle making 60 revolution per min find 1.Angular velocity 2.linear velocity 3.centripetal acceleration​

Answer 1

Solution :-

• Length of the string = 1m
• Frequency (n) = 60 rpm

(1) Angular velocity

⇛ ω = 2π n

First we need to convert rpm into rps in order to do that simply divide by 60

⇛ n = 60 / 60 = 1 rps

Now let's substitute the value of n in above equation ,

⇛ ω = 2 x 3.14 x 1

⇛ ω = 6.28 rad / s

(2) Linear velocity

As per the formula ,

⇛ v = rω

⇛ v = lω

( since the length of the string is the radius of the horizontal circle )

⇛ v = 1 x 6.28

⇛ v = 6.28 m / s

(3) Centripetal Acceleration

Centripetal acceleration is given by the formula,

⇛ a = v ² / r

( since the length of the string is the radius of the horizontal circle )

⇛ a = 39.4 / 1

⇛ a = 39.4 m / s²

Answer :-

• The angular acceleration of the stone is 6.28 rad /s
• The linear velocity of the stone = 6.28 m /s
• The centripetal acceleration of the stone is 39.4 m /s²

Answer 2

Explanation:

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