Question

Q. A stone is dropped into water from a bridge
44.1 m above the water. Time taken by the stone
to reach water is
(1) s
2) 3 s
(3) 2 s
(4) 4 s​

Answer 1

u = 0 m/s ( Stone dropped without any velocity)

$s = ut + \frac{1}{2} at {}^{2} \\ 44.1 = 0 + \frac{1}{2} \times 9.8 \times t {}^{2} \\ t {}^{2} = 4.5 \times 2 = 9 \\ t = \sqrt{9} = 3s$

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Answer 2

Answer:

3 s

Explanation:

S = ut+1/2 gt∧2

S=44.1

g=9.8

44.1=1/2×9.8×t∧2

from here we get t∧2=9

hence t=3