Q. A string is wound round the rim of a mounted flywheel of mass 20 kg and radius 20 cm. A steady pull of 25 N is applied on the cord. Neglecting friction and mass of the string, the angular acceleration of the wheel is
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The mass of flywheel = 20 kg
Radius= 20 cm
= 20/100m=1/5 m
The moment of inertia = 1/2MR^2=1/2×20×1/5
I = 0.4 kg−m^2
Angular acceleration = α=τ/I
= FR/I=25×15/0.4=12.5s^−2
Radius= 20 cm
= 20/100m=1/5 m
The moment of inertia = 1/2MR^2=1/2×20×1/5
I = 0.4 kg−m^2
Angular acceleration = α=τ/I
= FR/I=25×15/0.4=12.5s^−2
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